java計(jì)算兩點(diǎn)坐標(biāo)距離 求高手用JAVA幫我設(shè)計(jì)一個完整的Point類,可以計(jì)算兩點(diǎn)之間距離和中間點(diǎn)坐標(biāo)的,萬分感謝?
求高手用JAVA幫我設(shè)計(jì)一個完整的Point類,可以計(jì)算兩點(diǎn)之間距離和中間點(diǎn)坐標(biāo)的,萬分感謝?公共類點(diǎn){double x1,x2,y1,y2double d,x3,y3點(diǎn)(double x1,doub
求高手用JAVA幫我設(shè)計(jì)一個完整的Point類,可以計(jì)算兩點(diǎn)之間距離和中間點(diǎn)坐標(biāo)的,萬分感謝?
公共類點(diǎn){
double x1,x2,y1,y2
double d,x3,y3
點(diǎn)(double x1,double y1,double x2,double y2){//this.x1=x1
this.x2=x2
this.y1=y1
this.y2=y2
void TestPoint(){//y2)/2
d=數(shù)學(xué).sqrt((x1-x2)*(x1-x2)(y1-y2)*(y1-y2))系統(tǒng)輸出打印(“(”x3“,”y3“)”)系統(tǒng)輸出打印(d)
}
public static void main(String[]args){
Point p=新點(diǎn)(1,1,2,2)
p.TestPoint()
}
java求兩點(diǎn)距離?
public class Point{private double x private double y public Point(double x,double y){this.x=x this.y=y}public double getDistance(Point p){doubleu x=數(shù)學(xué).abs(this.x-p.x)doubleu y=數(shù)學(xué).abs(this.y-p.y)返回?cái)?shù)學(xué).sqrt(u x*u x u y*u y)}公共靜態(tài)void main(String[]args){Point p1=新點(diǎn)(5,5)Point p2=新點(diǎn)(10,10)系統(tǒng)輸出打?。╬2.getDistance(p1))}