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oracle if 多條件判斷 ORACLE查詢(xún)樹(shù)型關(guān)系是怎樣的?

ORACLE查詢(xún)樹(shù)型關(guān)系是怎樣的?相關(guān)介紹:在oracle中start with connect by (prior) 用來(lái)對(duì)樹(shù)形結(jié)構(gòu)的數(shù)據(jù)進(jìn)行查詢(xún)。其中start with conditon 給出的

ORACLE查詢(xún)樹(shù)型關(guān)系是怎樣的?

相關(guān)介紹:在oracle中start with connect by (prior) 用來(lái)對(duì)樹(shù)形結(jié)構(gòu)的數(shù)據(jù)進(jìn)行查詢(xún)。其中start with conditon 給出的是數(shù)據(jù)搜索范圍, connect by后面給出了遞歸查詢(xún)的條件,prior 關(guān)鍵字表示父數(shù)據(jù),prior 條件表示子數(shù)據(jù)需要滿(mǎn)足父數(shù)據(jù)的什么條件。思路:列出所有子,然后判斷所列出的子下面再?zèng)]有子了select * from (select ID, parentid from tb start with id="B" connect by prior parentid = idunionselect ID, parentid from tb start with id="G" connect by prior parentid = id ) Awhere not exsits ( select 1 from tb b where A.id= B. parentid)你試試,我沒(méi)有環(huán)境。